vanilla

An array is called vanilla if all its elements are made up of the same digit. For example {1, 1, 11, 1111, 1111111} is a vanilla array because all its elements use only the digit 1. However, the array {11, 101, 1111, 11111} is not a vanilla array because its elements use the digits 0 and 1. Write a method called isVanilla that returns 1 if its argument is a vanilla array. Otherwise it returns 0.

If you are writing in Java or C#, the function signature is

   int isVanilla(int[ ] a)

If you are writing in C or C++, the function signature is

  int isVanilla(int a[ ], int len) where len is the number of elements in the array a.

Example

if a is	Return	reason
{1}	1	all elements use only digit 1.
{11, 22, 13, 34, 125}	0	Elements used 5 different digits
{9, 999, 99999, -9999}	1	Only digit 9 is used by all elements. Note that negative numbers are okay.
{ }	1	There is no counterexample to the hypothesis that all elements use the same digit.

Solution :

  public int isVanilla(int [] a)

        {

            int rtnVal = 1, rem=0, n = 0, flag = 0;

            if (a.Length > 0)

                flag = a[0] % 10;

            for(int i=0;i<a.Length;i++)

            {

                if (a[i] < 0)

                    a[i] = -1 * a[i];

                n = a[i];

                while(n!=0)

                {

                    rem = n % 10;

                    n = n / 10;

                    if(rem!=flag)

                    {

                        rtnVal = 0;

                        goto label;

                    }

                }

            }

        label:

            return rtnVal;

        }