04:50
QUESTION : An array a is called paired if its even numbered elements (a[0], a[2],
etc.) are odd and its odd numbered elements
(a[1], a[3], etc.) are even.
Write a function namedisPaired that
accepts an array of integers and returns 1 if the array is paired, otherwise it returns 0.
Examples: {7, 2, 3, 6, 7}
is paired since a[0], a[2] and a[4] are odd,
a[1] and a[3] are even. {7, 15, 9, 2, 3} is not paired since a[1] is odd. {17, 6, 2,
4} is not paired since a[2] is even.
If you are programming in Java or C#, the
function signature is
int isPaired(int[ ] a)
If you are programming in C or C++, the function signature
is
int isPaired(int a[ ], int len)
where len is the number of elements in the
array.
public static int
isPaired(int [] a)
{
bool isOk1 =true, isOk2 = true;
for (int i = 0; i < a.Length;i++)
{
if(i%2==0)
{
if(a[i]%2==0)
{
isOk1 = false;
}
}
else
{
if (a[i] % 2 == 1)
{
isOk2 = false;
}
}
}
if(isOk1
&& isOk2)
{
return 1;
}
else
{
return 0;
}
}
Thanks for the solution
ReplyDeletecan you please check it for {} empty array
# this is a better code
ReplyDeletepublic static int ispaired(int[] a){
for(int i = 0; i < a.length; i++){
if( i % 2 == 0){
if ( a[i] % 2 == 0){ return 0;}
}
else{
if ( a[i] % 2 != 0){ return 0;}
}
}
return 1;
}